# Important Questions for Class 7 Chapter 9-Rational Numbers

For your benifit we have come up with sets of important CBSE questions across grades that are based on the latest syllabus and exam pattern. It gives step by step solution for all questions. Download the free PDF now!

Important questions based on NCERT syllabus for Class 7 Chapter 9 - Rational Numbers:

Question 1: An investor invested 20cr in a company for the development of a mobile application. Company distributed this money among various departments to cover up the needs, one-sixth of invested money is allocated to advertisement team . Two third of remaining money was given to development team. In development team there are two sub teams namely Graphics and content team. Among them it is distributed in such a way that content team will get 3/2times more money than that of graphics team. Find the money allocated to each team separately.
Solution:
Total money invested = 20cr Amount allocated to advertisement team = 20 x (1/4)= 5cr
Remaining amount = 20-5=15cr;
Two third of 15 cr is allocated for development team= 15 x 2/3 = 10cr
Let graphics team got x ,then content team got 3/2x. By solving x +3/2x =10 ;
x=4
Hence, amount allocated for graphics and content team were 4cr and 6cr respectively.

Question 2: Write the comment on the following rational numbers whether they are equal or greater or less than 19/26. The numbers are 247/338, 26/32 and 19/21.
Solution:
When we multiply by 13 in the numerator and the denominator we get 247/338 , therefore, 19/26 = 247/338.
By inspection, when numerator is same and denominator is different then the fraction having large value of denominator is smaller than the fraction having less value of denominator.
Hence 19/26< 19/21.
For comparing 19/26 and 13/16 we have to make the denominator of both the
fraction by taking LCM of 26 & 16 = 416.
19×16/26×16 = 304/416 ,
13×26/16×26 = 338/416 ;
338 > 304
Hence, 26/32 > 19/26

Question 3: Amit used to be on the playground 4 (1/2) times as much as his brother. His parents threatened him, so, he cut down to 1(1/3) of the time he used to play. How many times as much as his brother is he now on the ground?
Solution:
Amit played 9/2 times of his brother.
After threaten, duration of Amit play = 9/2-4/3 = 21/6 = 7/2
So, now Amit plays 7/2 times of his brother.