# Important Questions for Class 6 Chapter 14 - Practical Geometry

A very common notion among students to think that math is tough. With the right kind of attention and preparation, you can achieve good scores in math every time. For your benefit, our math subject experts have meticulously prepared a list of important questions for CBSE class 6 Math chapter-wise and topic-wise.

**Important questions based on NCERT syllabus for Class 6 Chapter 14 - Practical Geometry: **

*Question 1*: Draw an angle of measure 132° and construct its bisector.

*Solution*:

The below given steps should be followed to construct an angle and its bisector:

i) Draw a line l and mark a point ‘O’ on it. Class VI Practical geometry Mathematics

ii) Mark a point A at 132 ⁰ with the help of protractor. Join OA.

iii) Draw an arc of convenient radius , while taking point O as centre. Let it intersect both rays of angle 132 at point A and B.

v) Taking A and B as centres, draw arc of radius more than ½ ab in the interior of angle of 132⁰. Let those intersect each other at C . Join OC.

OC is the required bisector of angle of 132⁰.

*Question 2*: Draw a line 8.4 cm and divide it into four parts using compass.

*Solution*:

i) Draw a line segment XY of length 4.2 cm.

ii) Draw a circle, while taking point X as centre and radius more than half of XY.

iii) With same radius and taking centre as Y, again draw arcs to cut the circle at A and B. Join AB which intersects XY at M.

iv) Taking X and Y as centres. Draw two circles more than half of XM.

vi) With same radius and taking M as centre, draw arcs to intersect these circles at P,Q,R and S.

vii) Join PQ and RS. These are intersecting XY at T and U.

viii) Now XT =TM= MU=UY. These are 4 equal parts of XY.

*Question 3*: Draw a angle of 90⁰ and construct its bisector.

*Solution*: Steps of construction:

i) Make a right angled triangle using compass.

ii) With R and V as centre make arcs at any point in the mid of the angle.

iii) That point W will be the required point.

iv) Join P and W .PW is the required bisector.

*Question 4*: Draw an angle of measure 115° and construct its bisector.

*Solution*: The below given steps should be followed to construct an angle and its bisector:

i) Draw a line l and mark a point ‘O’ on it.

ii) Mark a point A at 115 ⁰ with the help of protractor. Join OA.

iii) Draw an arc of convenient radius, while taking point O as centre. Let it intersect both rays of angle 115 at point A and B.

iv) Taking A and B as centres, draw arc of radius more than ½ AB in the interior of angle of 115⁰.

Let those intersect each other at C.

Join OC.

OC is the required bisector of angle of 115⁰.

*Question 5*: Draw the circle with centre O using compass and ruler. Make smaller circles such that they are nonintersecting and passing through the point O and touches the circumference of bigger circle.

*Solution*: Steps of construction:

i) Draw a circle of radius of any radius.

ii) Draw a smaller circle of radius half of the radius of larger circle and at the midpoint of the radius in one direction.

iii) In the same way draw the smaller circle in the opposite direction.