CBSE NCERT Solutions for Class 7 Chapter 11

The solutions provide students a fine preparation strategy in order to prepare for their exam more methodically. Students get a fair idea on the subject, the sort of questions that are possibly asked and the method to answer them.

CBSE NCERT Solutions for Class 7 Maths Chapter 11:

Question-1:

Find the area of a square park whose perimeter is 320 m.

Solution:

Given: Perimeter of square park = 320 m
⇒ 4 x side = 320
⇒ side = 320/4 = 80 m
Now, Area of square park = side x side = 80 x 80 = 6400 m2
Thus, the area of square park is 6400 m2.

Question-2:

Find the breadth of a rectangular plot of land, if its area is 440 m2 and the length is 22 m. Also find its perimeter.

Solution:

Area of rectangular park = 440 m2
⇒ length x breadth = 440 m2
⇒ 22 x breadth = 440
⇒ breadth = 440 22 = 20 m
Now, Perimeter of rectangular park = 2 (length + breadth)
= 2 (22 + 20)
= 2 x 42 = 84 m
Thus, the perimeter of rectangular park is 84 m

Question-3:

A wire is in the shape of a rectangle. Its length is 40 cm and breadth is 22 cm. If the same wire is rebent in the shape of a square, what will be the measure of each side. Also find which shape encloses more area?

Solution:

According to the question, Perimeter of square = Perimeter of rectangle
⇒ 4 x side = 2 (length + breadth)
⇒ 4 x side = 2 (40 + 22) ⇒ 4 x side = 2 x 62
⇒ side = 2×62/4 = 31 cm
Thus, the side of the square is 31 cm.
Now, Area of rectangle = length x breadth = 40 x 22 = 880 cm2
And Area of square = side x side = 31 x 31 = 961 cm2
Therefore, on comparing, the area of square is greater than that of rectangle.