# CBSE NCERT Solutions for Class 7 Chapter 11

The solutions provide students a fine preparation strategy in order to prepare for their exam more methodically. Students get a fair idea on the subject, the sort of questions that are possibly asked and the method to answer them.

**CBSE NCERT Solutions for Class 7 Maths Chapter 11:**

*Question-1*:

Find the area of a square park whose perimeter is 320 m.

*Solution*:

Given: Perimeter of square park = 320 m

⇒ 4 x side = 320

⇒ side = 320/4 = 80 m

Now, Area of square park = side x side = 80 x 80 = 6400 m2

Thus, the area of square park is 6400 m2.

*Question-2*:

Find the breadth of a rectangular plot of land, if its area is 440 m2 and the length is 22 m. Also find its perimeter.

*Solution*:

Area of rectangular park = 440 m2

⇒ length x breadth = 440 m2

⇒ 22 x breadth = 440

⇒ breadth = 440 22 = 20 m

Now, Perimeter of rectangular park = 2 (length + breadth)

= 2 (22 + 20)

= 2 x 42 = 84 m

Thus, the perimeter of rectangular park is 84 m

*Question-3*:

A wire is in the shape of a rectangle. Its length is 40 cm and breadth is 22 cm. If the same wire is rebent in the shape of a square, what will be the measure of each side. Also find which shape encloses more area?

*Solution*:

According to the question, Perimeter of square = Perimeter of rectangle

⇒ 4 x side = 2 (length + breadth)

⇒ 4 x side = 2 (40 + 22) ⇒ 4 x side = 2 x 62

⇒ side = 2×62/4 = 31 cm

Thus, the side of the square is 31 cm.

Now, Area of rectangle = length x breadth = 40 x 22 = 880 cm2

And Area of square = side x side = 31 x 31 = 961 cm2

Therefore, on comparing, the area of square is greater than that of rectangle.