CBSE NCERT Solutions for Class 7 Chapter 10

NCERT Solutions are prepared by experts to provide accurate and easy solutions for all questions covered in class 6 to 10 NCERT textbooks. Get Chapter-wise NCERT Class 7 solutions to help students boost exam preparations and clear doubts.

CBSE NCERT Solutions for Class 7 Maths Chapter 10:

Question-1:

Examine whether you can construct triangle DEF such that EF= 7.2 cm ,angle E= 110 degree and angle F = 80 degree. Justify your answer.

Solution:

As the sum of two angles of triangles = 110° +80° = 190° .
Since, sum of all angles of triangle = 180°.
Therefore, construction of triangle is not possible.

Question-2:

Draw a line, say AB, take a point C outside it. Through C, draw a line parallel to AB using ruler and compasses only.

Solution:
To construct:
line-segment
A line, parallel to given line by using ruler and compasses.
Steps of construction:
(a) Draw a line-segment AB and take a point C outside AB.
(b) Take any point D on AB and join C to D.
(c) With D as centre and take convenient radius, draw an arc cutting AB at E and CD at F.
(d) With C as centre and same radius as in step 3, draw an arc GH cutting CD at i.
(e) With the same arc EF, draw the equal arc cutting GH at J.
(f) Join JC to draw a line l.

This is the required line AB l.

Question-3:

Construct ∆ XYZ in which XY = 4.5 cm, YZ = 5 cm and ZX = 6 cm.

Solution:
To construct: ∆XYZ, where XY = 4.5 cm, YZ = 5 cm and ZX = 6 cm
Steps of construction:
triangle
(a) Draw a line segment YZ = 5 cm.
(b) Taking Z as centre and radius 6 cm, draw an arc.
(c) Similarly, Z as centre and radius 6 cm, draw an arc which intersects first arc at point X.
(d) Join XY and XZ.
It is the required ∆XYZ.